Look at Vector([2,-1,1]) and let L=Span of (2,-1,1) = {t (2,-1,1) where t is real}. Notice L is a line through the origin in R

with(LinearAlgebra): with(plots):

a:=spacecurve({[2*t,-1*t,1*t,t=0..1]},color=red):

display(a);

Part A: Find a vector

Part 2: Find a vector

Part 3: In Maple, use spacecurve commands and display as above to show that all three vectors lie in the same plane but no 2 are on the same line [use different colors like black, blue, green..., and one display command like display(a,b,c);]

Part D: Describe all the vectors

you can use that will still span the plane - ie what

Part E: Find a vector

Part F: Add

Concrete mix, which is used in jobs as varied as making sidewalks and building bridges, is composed of five main materials: cement, water, sand, gravel, and fly ash. By varying the percentages of these materials, mixes of concrete can be produced with differing characteristics. For example, the water-to-cement ratio affects the strength of the final mix, the sand-to-gravel ratio affects the "workability" of the mix, and the fly-ash-to-cement ratio affects the durability. Since different jobs require concrete with different characteristics, it is important to be able to produce custom mixes.

Assume you are the manager of a building supply company and plan to keep on hand three basic mixes of concrete from which you will formulate custom mixes for your customers. The basic mixes have the following characteristics:

Super-Strong Type S | All-Purpose Type A | Long-Life Type L | |

Cement | 30 | 18 | 12 |

Water | 10 | 10 | 10 |

Sand | 5 | 25 | 15 |

Gravel | 5 | 5 | 15 |

Fly ash | 10 | 2 | 8 |

Part A: Give a practical interpretation to the linear combination 3S+5A+2L by discussing the resulting strength (low water to cement ratio), workability (high sand to gravel ratio), and durability (high fly ash to cement ratio) of the mix and comparing it to those of S,A and L.

Part B: What does Span{S,A,L} = {a S + b A + c L where a, b, and c are real numbers} represent?

Part C: A customer requests 6 kg of (6000 g) of a custom mix with the following proportions of cement, water, sand, gravel, and fly ash: 18:10:19:8:5. Is it possible to make using only S, A and L? If so, find the number of scoops of the basic mixes (S, A, and L) needed to create this mix.

Part D: If there is a solution in Part C, is the solution unique? Explain.

Part E: Let V=Vector([18,10,19,8,5]). Is S, A, L, V linearly independent? Show work and relate your explanation to the definition of l.i.

Part F: Explain why any combination of S,A,L and V can also be achieved by a combination of just S,A, and L, ie that V is redundant.

Part G: Let U=Vector([12,12,12,12,12]). Show that {S,A,L,U} is a linearly independent set of vectors. What practical advantage does that have?

Part H: Define a fifth basic mix W to add to {S,A,L,U} such that any custom mixture can be expressed as a linear combination of the set of mixes {S,A,L,U,W}.

Part I: Why will there still be mixes that cannot be physically produced from this set of five basic mixes? Give an example where this happens.